From this equation you deserve to see the the ratio of mole of O2 to H2O is 25:18. If you understand how countless moles that oxygen is consumed, multiply it by 18/25 will give you the number of moles the water is produced. Due to the fact that we recognize that 5.4 grams of O2 is consumed, we can calculated the lot of water produced. 5.4g O2 represents 5.4/32 mole of O2, i beg your pardon is equal to 0.16875 moles of O2.

Therefore, 18/25 • 0.16875 = moles of water produced = 0.1215 moles H2O. Since the inquiry asks the massive of water produced, us multiply by the molecular weight of water : 18 • 0.1213 = 2.187 grams that water.

You are watching: Liquid octane reacts with oxygen gas to form carbon dioxide gas and water vapor


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