how do you deal with displaystyleleft(lnleft(x ight) ight)^2+2lnleft(x ight)=+15 ?
displaystylex=e^left(-5 ight)left(aaa ight)x=e^3 or displaystylex=.0067379left(aaa ight)x=20.0855 Explanation: displaystyleleft(lnleft(x ight) ight)^2+2lnleft(x ight)=15 ...

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displaystylex=e^frac12left( extXXX ight)quad extorquadleft( extXXX ight)x=e^-1 Explanation:Letdisplaystylea=lnleft(x ight) ...
how do you distinguish displaystylefleft(x ight)=lnx^2+lnx-x making use of the sum rule?
displaystylef'left(x ight)=frac3x-1 Explanation:Differentiate each term personal to attain displaystylef'left(x ight)=frac2x+frac1x-1
displaystylex=sqrt<5>frac1e^2 Explanation: displaystyleleft<1 ight> ext lnx^2+lnx^3+2=0 Property:displaystylelog_bm+log_bn=log_bleft(mn ight) ...
exactly how do you identify displaystylefleft(x ight)=x^3lnleft(x ight)-lnleft(x^4 ight) ?
displaystylex^2+3x^2lnleft(x ight)-frac4x Explanation:You can differentiate the 2 terms separately, for this reason I'll go with one at a time. displaystylefracdleft.dx ight.left ...

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displaystyle-7lnx=lnleft(x^-7 ight) Explanation:Step 1:Using the addition rule thatdisplaystylelnleft(a ight)+lnleft(b ight)=lnleft(ab ight) ...
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left< eginarray l l 2 & 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 & 0 & 3 \ -1 & 1 & 5 endarray ight>
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